(x^2/16)-(y^2/4)=1

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Solution for (x^2/16)-(y^2/4)=1 equation: 


x in (-oo:+oo)

(x^2)/16-((y^2)/4) = 1 // - 1

(x^2)/16-((y^2)/4)-1 = 0

1/16*x^2 = -(-1/4*y^2-1) // : 1/16

x^2 = 16*(1-(-1/4*y^2))

x^2 = 16*(1/4*y^2+1) // ^ 1/2

abs(x) = 4*(1/4*y^2+1)^(1/2)

x = 4*(1/4*y^2+1)^(1/2) or x = -(4*(1/4*y^2+1)^(1/2))

x in { 4*(1/4*y^2+1)^(1/2), -(4*(1/4*y^2+1)^(1/2)) }

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